2x^2+50x-46875=0

Solution for 2x^2+50x-46875=0 equation:

2x^2+50x-46875=0

a = 2; b = 50; c = -46875;
Δ = b2-4ac
Δ = 502-4·2·(-46875)
Δ = 377500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{377500}=\sqrt{2500*151}=\sqrt{2500}*\sqrt{151}=50\sqrt{151}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-50\sqrt{151}}{2*2}=\frac{-50-50\sqrt{151}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+50\sqrt{151}}{2*2}=\frac{-50+50\sqrt{151}}{4}
$